Well the difference in the capacitor energies is:
##ΔE_c=(frac{1}{2}(Q_o+q)^C_1+\frac{1}{2}(q)^2/C_2)-\frac{1}{2}(Q_o)^2/C_1=-150uJ##
The work of the generator is ##Eq=-100uJ##
Since ##-250uJ## wasnt's correct i guess the equation is
##ΔE=ΔE_c-Eq=-50uJ## but why is it ##-Eq## we are subtracting...
Homework Statement
This is a problem from some textbook a friend emailed me:
The text goes like this:
When the switch is open the charge on ##C1## equals ##Q_o=40uC## and ##C_2## has no charge on it. The switch closes and some charge ##q## flows through the capacitors (suppose the flow to be...
Homework Statement
Starting from the expression of the Delta-Y resistor transformation work out the conductance transformation equation.
Homework Equations
3. The Attempt at a Solution [/B]
I will just be using one equation as others are done analogically. My Δ has ##(R_{12},R_{23},R_{13})##...
Sure, here it is:
And here is the original text:
"The switch is open in state 1 and then it closes. During the time until the stationary condition appears, ##+2uC## of charge flows through the wire with ##C_1## Calculate the amount that goes through the wire with ##C_2##."
Using this...
Homework Statement
From the circuit diagram ( http://postimg.org/image/lldnr7mf7/ ) calculate the net charge flown through the capacitor 2.
Homework Equations
3. The Attempt at a Solution [/B]
I actually don't need to solve the full problem as i understand how, what i have trouble with is the...
Homework Statement
$$\lim_{x\to\infty} \left(\frac{n^2+2n+1}{n^2+2n+3}\right)^{\frac{2n^2}{n+1}}$$
Homework Equations
3. The Attempt at a Solution [/B]
I tried
##\lim_{x\to\infty} \left(\frac{n^2+2n+3-2}{n^2+2n+3}\right)^{\frac{2n^2}{n+1}}=##
##\lim_{x\to\infty}...
Homework Statement
For a given system, a conducting cylinder with radius ##r=a## with a linear charge density ##Q'## and a conducting surface at a distance ##z=h## from the cylinder, calculate the linear capacitance of the cylinder.Take that ##h>>a##
##C'=\frac{Q'}{U}##
Homework Equations
3...